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GCSE Chemistry

Quantitative Chemistry

Conservation of mass, moles, concentrations, and yields.

Conservation of Mass and Balancing Equations

In a chemical reaction, mass is always conserved. The total mass of reactants equals the total mass of products. No atoms are created or destroyed — they are rearranged.

Balancing equations: the number of atoms of each element must be the same on both sides.

Example: Mg + O₂ → MgO (unbalanced) Balanced: 2Mg + O₂ → 2MgO

State symbols: (s) solid, (l) liquid, (g) gas, (aq) aqueous (dissolved in water)

Key Points

  • Never change the formulae — only change the numbers in front
  • Balance the most complex molecule first
  • Check each element has the same count on both sides
  • If mass appears to change, a gas may have escaped or been absorbed

Example Questions

2Balance this equation: Fe₂O₃ + C → Fe + CO₂

2Fe₂O₃ + 3C → 4Fe + 3CO₂. Check: Fe: 4=4 ✓, O: 6=6 ✓, C: 3=3 ✓

[2 marks]

2When calcium carbonate is heated, the mass of the solid decreases. Explain why, given that mass is conserved.

CaCO₃ → CaO + CO₂. Carbon dioxide gas is produced and escapes into the atmosphere. The total mass is conserved, but the mass of the solid residue decreases because CO₂ has been lost as a gas.

[2 marks]

Moles and Calculations

The mole is a measure of the amount of substance. One mole contains 6.02 × 10²³ particles (Avogadro's constant).

Key formulae: - Moles = mass ÷ relative formula mass (Mr) - Mass = moles × Mr - Mr = sum of all relative atomic masses in the formula

Example: Mr of H₂O = (2 × 1) + 16 = 18 If you have 36g of water: moles = 36 ÷ 18 = 2 moles

Concentration (mol/dm³) = moles ÷ volume (dm³) Remember: 1 dm³ = 1000 cm³

Key Points

  • Use the periodic table for relative atomic masses
  • Convert cm³ to dm³ by dividing by 1000
  • In titration calculations, use the balanced equation ratio
  • Excess reactant is the one left over after the reaction

Example Questions

2Calculate the number of moles in 11g of carbon dioxide (CO₂).

Mr of CO₂ = 12 + (2 × 16) = 44. Moles = 11 ÷ 44 = 0.25 moles

[2 marks]

325.0 cm³ of 0.1 mol/dm³ NaOH reacts with HCl: NaOH + HCl → NaCl + H₂O. Calculate the concentration of HCl if 20.0 cm³ was needed.

Moles NaOH = 0.1 × (25/1000) = 0.0025 mol. Ratio 1:1, so moles HCl = 0.0025. Concentration = 0.0025 ÷ (20/1000) = 0.125 mol/dm³

[3 marks]