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GCSE Physics

Forces

Newton's laws, momentum, stopping distances, and pressure.

Forces and Their Effects

A force is a push or pull acting on an object. Forces are measured in newtons (N) and are vectors (they have magnitude and direction).

Contact forces: friction, air resistance, tension, normal contact force Non-contact forces: gravity, electrostatic, magnetic

Weight = mass × gravitational field strength (W = mg) On Earth, g ≈ 10 N/kg

Resultant force: the single force that has the same effect as all forces acting together. If forces are balanced (resultant = 0), the object stays still or moves at constant velocity.

Key Points

  • Balanced forces = no acceleration (Newton's 1st Law)
  • Unbalanced forces = acceleration (Newton's 2nd Law: F = ma)
  • Every action has an equal and opposite reaction (Newton's 3rd Law)
  • Free body diagrams show all forces acting on an object

Example Questions

2A car of mass 1500 kg accelerates at 2 m/s². Calculate the resultant force.

F = ma = 1500 × 2 = 3000 N

[2 marks]

3Explain why a skydiver reaches terminal velocity.

Initially, gravity > air resistance, so the skydiver accelerates downwards. As speed increases, air resistance increases. Eventually air resistance equals weight — the forces are balanced, resultant force is zero, and the skydiver falls at a constant speed (terminal velocity).

[3 marks]

Momentum

Momentum is a property of moving objects.

Momentum = mass × velocity (p = mv) Unit: kg m/s

Conservation of momentum: In a closed system, the total momentum before = total momentum after an event (collision or explosion).

Impulse = change in momentum = force × time (FΔt = mΔv)

This is why: cars have crumple zones (increase collision time → reduce force), airbags, seatbelts.

Key Points

  • Momentum is a vector — direction matters
  • In collisions, momentum is always conserved
  • Longer collision time = smaller force (F = Δp/Δt)
  • Safety features increase collision time to reduce injury force

Example Questions

3A 70 kg person is in a car travelling at 15 m/s. The car crashes and stops in 0.5 s. Calculate the average force on the person.

Change in momentum = 70 × 15 = 1050 kg m/s. Force = 1050 / 0.5 = 2100 N

[3 marks]